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notes 1
100問 • 1年前
  • Nayan Kumar
  • 通報

    問題一覧

  • 1

    √2 & 0

  • 2

    t

  • 3

    5√2

  • 4

    -4m/s² i

  • 5

    √5/4 m/s

  • 6

    4

  • 7

    60°

  • 8

    t

  • 9

    t

  • 10

    1

  • 11

    t

  • 12

    t

  • 13

    5/√2 m/s² North East

  • 14

    5√2

  • 15

    √5 m/s

  • 16

    Length of the given graph represents

    path or equation of trajectory

  • 17

    Path followed by the object can be determined by relation between X and y

    t

  • 18

    Relation between X and y position represents path of object

    t

  • 19

    parabolic path

  • 20

    circular path

  • 21

    elliptical path

  • 22

    straight line path

  • 23

    parabolic path

  • 24

    t

  • 25

    Projectile motion is non uniform motion with uniform acceleration

    t

  • 26

    t

  • 27

    t

  • 28

    Projectile motion is uniform motion along x-axis

    t

  • 29

    t

  • 30

    t

  • 31

    t

  • 32

    3

  • 33

    2

  • 34

    t

  • 35

    T1=T2

  • 36

    t

  • 37

    3

  • 38

    4

  • 39

    3

  • 40

    Recheck

    2

  • 41

    2

  • 42

    1

  • 43

    2

  • 44

    Ball is projected at 41° & 48 ° then range at 41° is R1 & at 48° is R2 (u=same )

    R1<R2

  • 45

    1

  • 46

    Two projectiles of same mass with same velocity are thrown at an angle 60° and 30° with the horizontal then which quantity will remain same

    horizontal range of projectile

  • 47

    1

  • 48

    4

  • 49

    1

  • 50

    2

  • 51

    4

  • 52

    2

  • 53

    Ball is Projected with same speed at two different angle a and b then range same at both angle, then find range in terms of their height h1 & h2

    4√ H1 H2

  • 54

    Right long and short form of equation of trajectory in ground to ground projectile motion

    t

  • 55

    2

  • 56

    3

  • 57

    3

  • 58

    A projectile is fired at an angle θ with you velocity then calculate its total angular displacement

  • 59

    Condition in ground to ground projectile motion so that object will we seem to moving perpendicular to initial direction of projection

    θ greater than or equal to 45 °

  • 60

    t

  • 61

    t

  • 62

    t

  • 63

    3

  • 64

    3

  • 65

    3

  • 66

    3

  • 67

    t

  • 68

    3s

  • 69

    1

  • 70

    t

  • 71

    t

  • 72

    At highest point of the path of projectile speed is zero

    f

  • 73

    Horizontal velocity zero at highest point of projectile

    f

  • 74

    1

  • 75

    2

  • 76

    1

  • 77

    Also calculate minimum velocity so that it will fall on nth step

    t

  • 78

    t

  • 79

    t

  • 80

    t

  • 81

    6s & 30√3m

  • 82

    t

  • 83

    2

  • 84

    t

  • 85

    3

  • 86

    2

  • 87

    t

  • 88

    Find magnitude

    10m/s

  • 89

    t

  • 90

    50√2 m

  • 91

    Calculate minimum time to acquire d min

    0.5s

  • 92

    40/√2m

  • 93

    60m

  • 94

    2

  • 95

    t

  • 96

    1

  • 97

    Recheck

    2

  • 98

    3

  • 99

    2

  • 100

    2

  • class questions

    class questions

    Nayan Kumar · 8問 · 1年前

    class questions

    class questions

    8問 • 1年前
    Nayan Kumar

    dpp questions

    dpp questions

    Nayan Kumar · 8問 · 1年前

    dpp questions

    dpp questions

    8問 • 1年前
    Nayan Kumar

    mistakes previous year

    mistakes previous year

    Nayan Kumar · 47問 · 1年前

    mistakes previous year

    mistakes previous year

    47問 • 1年前
    Nayan Kumar

    silly mistake

    silly mistake

    Nayan Kumar · 15問 · 1年前

    silly mistake

    silly mistake

    15問 • 1年前
    Nayan Kumar

    data and facts

    data and facts

    Nayan Kumar · 18問 · 1年前

    data and facts

    data and facts

    18問 • 1年前
    Nayan Kumar

    notes

    notes

    Nayan Kumar · 38問 · 1年前

    notes

    notes

    38問 • 1年前
    Nayan Kumar

    notes 1 from constant acceleration

    notes 1 from constant acceleration

    Nayan Kumar · 100問 · 1年前

    notes 1 from constant acceleration

    notes 1 from constant acceleration

    100問 • 1年前
    Nayan Kumar

    Learn fast

    Learn fast

    Nayan Kumar · 29問 · 1年前

    Learn fast

    Learn fast

    29問 • 1年前
    Nayan Kumar

    notes 2 from motion under gravity

    notes 2 from motion under gravity

    Nayan Kumar · 7問 · 1年前

    notes 2 from motion under gravity

    notes 2 from motion under gravity

    7問 • 1年前
    Nayan Kumar

    frog

    frog

    Nayan Kumar · 44問 · 1年前

    frog

    frog

    44問 • 1年前
    Nayan Kumar

    notes questions

    notes questions

    Nayan Kumar · 71問 · 1年前

    notes questions

    notes questions

    71問 • 1年前
    Nayan Kumar

    notes 1 electrolytic cell

    notes 1 electrolytic cell

    Nayan Kumar · 66問 · 1年前

    notes 1 electrolytic cell

    notes 1 electrolytic cell

    66問 • 1年前
    Nayan Kumar

    問題一覧

  • 1

    √2 & 0

  • 2

    t

  • 3

    5√2

  • 4

    -4m/s² i

  • 5

    √5/4 m/s

  • 6

    4

  • 7

    60°

  • 8

    t

  • 9

    t

  • 10

    1

  • 11

    t

  • 12

    t

  • 13

    5/√2 m/s² North East

  • 14

    5√2

  • 15

    √5 m/s

  • 16

    Length of the given graph represents

    path or equation of trajectory

  • 17

    Path followed by the object can be determined by relation between X and y

    t

  • 18

    Relation between X and y position represents path of object

    t

  • 19

    parabolic path

  • 20

    circular path

  • 21

    elliptical path

  • 22

    straight line path

  • 23

    parabolic path

  • 24

    t

  • 25

    Projectile motion is non uniform motion with uniform acceleration

    t

  • 26

    t

  • 27

    t

  • 28

    Projectile motion is uniform motion along x-axis

    t

  • 29

    t

  • 30

    t

  • 31

    t

  • 32

    3

  • 33

    2

  • 34

    t

  • 35

    T1=T2

  • 36

    t

  • 37

    3

  • 38

    4

  • 39

    3

  • 40

    Recheck

    2

  • 41

    2

  • 42

    1

  • 43

    2

  • 44

    Ball is projected at 41° & 48 ° then range at 41° is R1 & at 48° is R2 (u=same )

    R1<R2

  • 45

    1

  • 46

    Two projectiles of same mass with same velocity are thrown at an angle 60° and 30° with the horizontal then which quantity will remain same

    horizontal range of projectile

  • 47

    1

  • 48

    4

  • 49

    1

  • 50

    2

  • 51

    4

  • 52

    2

  • 53

    Ball is Projected with same speed at two different angle a and b then range same at both angle, then find range in terms of their height h1 & h2

    4√ H1 H2

  • 54

    Right long and short form of equation of trajectory in ground to ground projectile motion

    t

  • 55

    2

  • 56

    3

  • 57

    3

  • 58

    A projectile is fired at an angle θ with you velocity then calculate its total angular displacement

  • 59

    Condition in ground to ground projectile motion so that object will we seem to moving perpendicular to initial direction of projection

    θ greater than or equal to 45 °

  • 60

    t

  • 61

    t

  • 62

    t

  • 63

    3

  • 64

    3

  • 65

    3

  • 66

    3

  • 67

    t

  • 68

    3s

  • 69

    1

  • 70

    t

  • 71

    t

  • 72

    At highest point of the path of projectile speed is zero

    f

  • 73

    Horizontal velocity zero at highest point of projectile

    f

  • 74

    1

  • 75

    2

  • 76

    1

  • 77

    Also calculate minimum velocity so that it will fall on nth step

    t

  • 78

    t

  • 79

    t

  • 80

    t

  • 81

    6s & 30√3m

  • 82

    t

  • 83

    2

  • 84

    t

  • 85

    3

  • 86

    2

  • 87

    t

  • 88

    Find magnitude

    10m/s

  • 89

    t

  • 90

    50√2 m

  • 91

    Calculate minimum time to acquire d min

    0.5s

  • 92

    40/√2m

  • 93

    60m

  • 94

    2

  • 95

    t

  • 96

    1

  • 97

    Recheck

    2

  • 98

    3

  • 99

    2

  • 100

    2