notes 1 from constant acceleration

100問 • 1年前

Nayan Kumar

通報

問題一覧

Ball is dropped from height H and it travelled 7H/16 in last sec of Journey, then find height H

80m

845m

20m

10sec

300m

18m/s

-3m/sec ²

Object starts its motion with velocity 10m/s after 8sec it's velocity becomes 24m/s then find total displacement in this interval

136m

Object starts his motion from rest and constant acceleration then find ratio of displacement in nth sec to n sec

2/n -1/n²

Object starts its Motion with rest and constant acceleration then find ratio of displacement in 6thsec to 6sec

11/36

If object starts his motion from rest and constant acceleration then its displacement and distance will be same

true

Object starts its motion with rest and constant acceleration then find the ratio of distance in 1sec :2sec:3sec

1:4:9

Object starts its motion with rest and constant acceleration then find the ratio of displacement in tsec and 2t sec

1:4

1:4:9

320m

1:3:5

S1=S2/3

Object starts its motion with rest and constant acceleration then find the ratio of displacement travelled by the body during the 4th sec and 3rd sec

7/5

300m

412.5m

Obviously start is Motion from u and constant acceleration then find velocity at mid point if velocity at end point is v

Objects start motion with constant acceleration a and velocity u then find its velocity at 1/3 displacement of complete journey final velocity is v

Stopping distance formula

-20m/s²

Write all equation of motion all six

Acceleration does not represent motion

24m

0.5m

400m

7:9

25√2km/h

y=4x

120m

112m

go on increasing with time

2v/a

1m/s

If velocity and acceleration are in same direction then U turn is possible

False

velocity and acceleration are in opposite direction then U turn is possible only when v=0

true

The initial velocity of a particle is 20m/s and retardation 2m/s² then find distance in 10 sec

100m

The initial velocity of a particle is 20 m per second and retardation 2m/s² then find distance and displacement in 10th sec

1m and 1m

29m

The initial velocity of a particle is 21m/s and retardation is 2 m per second square then distance in 11th second

0.5m

The initial velocity of a particle is 21m/s and retardation is 2 m per second square then displacement in 11th second

A body is moving with uniform acceleration describe 40 m in the first 5 second and 65 m in next 5 second its initial velocity will be

5.5m/s

Object starts is Motion from rest and constant acceleration takes time T for S displacement then time taken for first half and second half displacement is

Object starts is Motion from rest and constant acceleration and travels with acceleration a for some time t1 then it retards with B and comes to at rest in time t2 then find total distance travelled and Vmax Write all for formulas of rest 2 rest motion

A body starts from rest and acceleration 2 m per second square till it attains the maximum velocity then returnas to rest with 3 m per second square is total time is 10 seconds then maximum speed

12 m per second

29m

260m

Find displacement in the given question not distance

240m

Motion under gravity Draw graph for v=gt S=1/2gt² Acceleration versus time

80m

A body falls from rest in the gravity of earth and distance travelled in 5th second is

45m

A body falls from rest in the gravity of earth and distance travelled in 45th second is

445m

20 m per second

125m

both

Answer in fraction

5/3m

3.75m

Ball is projected upward with velocity 50 m/s then find time of flight

10 second

Ball is projected upward with velocity 50 m/s then find maximum height

125 m

Ball is projected upward with velocity 50 m/s then find displacement in 6 second

120m

Ball is projected upward with velocity 50 m/s then find height at 7 second

105 m

Ball is projected upward with velocity 50 m/s then find average velocity in 8 second

10 m per second

Ball is projected upward with velocity 50 m/s then find average speed in 8 second

170/8 meter per second

20 m/s and 200/8 m/s

20 m

845 m

80 m

96 m

8H/9

5 second

7 second

105 m

125 m

6 second

10 second

20 m

6 second

100

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25問 • 1年前

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問題一覧

Ball is dropped from height H and it travelled 7H/16 in last sec of Journey, then find height H

80m

845m

20m

10sec

300m

18m/s

-3m/sec ²

Object starts its motion with velocity 10m/s after 8sec it's velocity becomes 24m/s then find total displacement in this interval

136m

Object starts his motion from rest and constant acceleration then find ratio of displacement in nth sec to n sec

2/n -1/n²

Object starts its Motion with rest and constant acceleration then find ratio of displacement in 6thsec to 6sec

11/36

If object starts his motion from rest and constant acceleration then its displacement and distance will be same

true

Object starts its motion with rest and constant acceleration then find the ratio of distance in 1sec :2sec:3sec

1:4:9

Object starts its motion with rest and constant acceleration then find the ratio of displacement in tsec and 2t sec

1:4

1:4:9

320m

1:3:5

S1=S2/3

Object starts its motion with rest and constant acceleration then find the ratio of displacement travelled by the body during the 4th sec and 3rd sec

7/5

300m

412.5m

Obviously start is Motion from u and constant acceleration then find velocity at mid point if velocity at end point is v

Objects start motion with constant acceleration a and velocity u then find its velocity at 1/3 displacement of complete journey final velocity is v

Stopping distance formula

-20m/s²

Write all equation of motion all six

Acceleration does not represent motion

24m

0.5m

400m

7:9

25√2km/h

y=4x

120m

112m

go on increasing with time

2v/a

1m/s

If velocity and acceleration are in same direction then U turn is possible

False

velocity and acceleration are in opposite direction then U turn is possible only when v=0

true

The initial velocity of a particle is 20m/s and retardation 2m/s² then find distance in 10 sec

100m

The initial velocity of a particle is 20 m per second and retardation 2m/s² then find distance and displacement in 10th sec

1m and 1m

29m

The initial velocity of a particle is 21m/s and retardation is 2 m per second square then distance in 11th second

0.5m

The initial velocity of a particle is 21m/s and retardation is 2 m per second square then displacement in 11th second

A body is moving with uniform acceleration describe 40 m in the first 5 second and 65 m in next 5 second its initial velocity will be

5.5m/s

Object starts is Motion from rest and constant acceleration takes time T for S displacement then time taken for first half and second half displacement is

A body starts from rest and acceleration 2 m per second square till it attains the maximum velocity then returnas to rest with 3 m per second square is total time is 10 seconds then maximum speed

12 m per second

29m

260m

Find displacement in the given question not distance

240m

Motion under gravity Draw graph for v=gt S=1/2gt² Acceleration versus time

80m

A body falls from rest in the gravity of earth and distance travelled in 5th second is

45m

A body falls from rest in the gravity of earth and distance travelled in 45th second is

445m

20 m per second

125m

both

Answer in fraction

5/3m

3.75m

Ball is projected upward with velocity 50 m/s then find time of flight

10 second

Ball is projected upward with velocity 50 m/s then find maximum height

125 m

Ball is projected upward with velocity 50 m/s then find displacement in 6 second

120m

Ball is projected upward with velocity 50 m/s then find height at 7 second

105 m

Ball is projected upward with velocity 50 m/s then find average velocity in 8 second

10 m per second

Ball is projected upward with velocity 50 m/s then find average speed in 8 second

170/8 meter per second

20 m/s and 200/8 m/s

20 m

845 m

80 m

96 m

8H/9

5 second

7 second

105 m

125 m

6 second

10 second

20 m

6 second

100