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notes 1 from constant acceleration
100問 • 1年前
  • Nayan Kumar
    • 通報

    問題一覧

  • 1

    Ball is dropped from height H and it travelled 7H/16 in last sec of Journey, then find height H

    80m

  • 2

    845m

  • 3

    20m

  • 4

    10sec

  • 5

    300m

  • 6

    18m/s

  • 7

    -3m/sec ²

  • 8

    Object starts its motion with velocity 10m/s after 8sec it's velocity becomes 24m/s then find total displacement in this interval

    136m

  • 9

    Object starts his motion from rest and constant acceleration then find ratio of displacement in nth sec to n sec

    2/n -1/n²

  • 10

    Object starts its Motion with rest and constant acceleration then find ratio of displacement in 6thsec to 6sec

    11/36

  • 11

    If object starts his motion from rest and constant acceleration then its displacement and distance will be same

    true

  • 12

    Object starts its motion with rest and constant acceleration then find the ratio of distance in 1sec :2sec:3sec

    1:4:9

  • 13

    Object starts its motion with rest and constant acceleration then find the ratio of displacement in tsec and 2t sec

    1:4

  • 14

    1:4

  • 15

    1:4:9

  • 16

    320m

  • 17

    1:3:5

  • 18

    S1=S2/3

  • 19

    Object starts its motion with rest and constant acceleration then find the ratio of displacement travelled by the body during the 4th sec and 3rd sec

    7/5

  • 20

    300m

  • 21

    412.5m

  • 22

    Obviously start is Motion from u and constant acceleration then find velocity at mid point if velocity at end point is v

    t

  • 23

    Objects start motion with constant acceleration a and velocity u then find its velocity at 1/3 displacement of complete journey final velocity is v

    t

  • 24

    t

  • 25

    Stopping distance formula

    t

  • 26

    -20m/s²

  • 27

    Write all equation of motion all six

    t

  • 28

    Acceleration does not represent motion

    t

  • 29

    1

  • 30

    0m

  • 31

    24m

  • 32

    0.5m

  • 33

    400m

  • 34

    7:9

  • 35

    25√2km/h

  • 36

    y=4x

  • 37

    120m

  • 38

    112m

  • 39

    16

  • 40

    3

  • 41

    go on increasing with time

  • 42

    1

  • 43

    1m

  • 44

    2v/a

  • 45

    1m/s

  • 46

    If velocity and acceleration are in same direction then U turn is possible

    False

  • 47

    velocity and acceleration are in opposite direction then U turn is possible only when v=0

    true

  • 48

    1m

  • 49

    The initial velocity of a particle is 20m/s and retardation 2m/s² then find distance in 10 sec

    100m

  • 50

    The initial velocity of a particle is 20 m per second and retardation 2m/s² then find distance and displacement in 10th sec

    1m and 1m

  • 51

    29m

  • 52

    The initial velocity of a particle is 21m/s and retardation is 2 m per second square then distance in 11th second

    0.5m

  • 53

    The initial velocity of a particle is 21m/s and retardation is 2 m per second square then displacement in 11th second

    0

  • 54

    A body is moving with uniform acceleration describe 40 m in the first 5 second and 65 m in next 5 second its initial velocity will be

    5.5m/s

  • 55

    Object starts is Motion from rest and constant acceleration takes time T for S displacement then time taken for first half and second half displacement is

    t

  • 56

    Object starts is Motion from rest and constant acceleration and travels with acceleration a for some time t1 then it retards with B and comes to at rest in time t2 then find total distance travelled and Vmax Write all for formulas of rest 2 rest motion

    t

  • 57

    A body starts from rest and acceleration 2 m per second square till it attains the maximum velocity then returnas to rest with 3 m per second square is total time is 10 seconds then maximum speed

    12 m per second

  • 58

    4

  • 59

    1

  • 60

    29m

  • 61

    260m

  • 62

    Find displacement in the given question not distance

    240m

  • 63

    Motion under gravity Draw graph for v=gt S=1/2gt² Acceleration versus time

    t

  • 64

    80m

  • 65

    A body falls from rest in the gravity of earth and distance travelled in 5th second is

    45m

  • 66

    A body falls from rest in the gravity of earth and distance travelled in 45th second is

    445m

  • 67

    t

  • 68

    20 m per second

  • 69

    125m

  • 70

    125m

  • 71

    both

  • 72

    Answer in fraction

    5/3m

  • 73

    3.75m

  • 74

    Ball is projected upward with velocity 50 m/s then find time of flight

    10 second

  • 75

    Ball is projected upward with velocity 50 m/s then find maximum height

    125 m

  • 76

    Ball is projected upward with velocity 50 m/s then find displacement in 6 second

    120m

  • 77

    Ball is projected upward with velocity 50 m/s then find height at 7 second

    105 m

  • 78

    Ball is projected upward with velocity 50 m/s then find average velocity in 8 second

    10 m per second

  • 79

    Ball is projected upward with velocity 50 m/s then find average speed in 8 second

    170/8 meter per second

  • 80

    20 m/s and 200/8 m/s

  • 81

    3

  • 82

    2

  • 83

    20 m

  • 84

    845 m

  • 85

    80 m

  • 86

    96 m

  • 87

    t

  • 88

    8H/9

  • 89

    5 second

  • 90

    7 second

  • 91

    105 m

  • 92

    t

  • 93

    2

  • 94

    125 m

  • 95

    6 second

  • 96

    t

  • 97

    10 second

  • 98

    20 m

  • 99

    6 second

  • 100

    t

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    問題一覧

  • 1

    Ball is dropped from height H and it travelled 7H/16 in last sec of Journey, then find height H

    80m

  • 2

    845m

  • 3

    20m

  • 4

    10sec

  • 5

    300m

  • 6

    18m/s

  • 7

    -3m/sec ²

  • 8

    Object starts its motion with velocity 10m/s after 8sec it's velocity becomes 24m/s then find total displacement in this interval

    136m

  • 9

    Object starts his motion from rest and constant acceleration then find ratio of displacement in nth sec to n sec

    2/n -1/n²

  • 10

    Object starts its Motion with rest and constant acceleration then find ratio of displacement in 6thsec to 6sec

    11/36

  • 11

    If object starts his motion from rest and constant acceleration then its displacement and distance will be same

    true

  • 12

    Object starts its motion with rest and constant acceleration then find the ratio of distance in 1sec :2sec:3sec

    1:4:9

  • 13

    Object starts its motion with rest and constant acceleration then find the ratio of displacement in tsec and 2t sec

    1:4

  • 14

    1:4

  • 15

    1:4:9

  • 16

    320m

  • 17

    1:3:5

  • 18

    S1=S2/3

  • 19

    Object starts its motion with rest and constant acceleration then find the ratio of displacement travelled by the body during the 4th sec and 3rd sec

    7/5

  • 20

    300m

  • 21

    412.5m

  • 22

    Obviously start is Motion from u and constant acceleration then find velocity at mid point if velocity at end point is v

    t

  • 23

    Objects start motion with constant acceleration a and velocity u then find its velocity at 1/3 displacement of complete journey final velocity is v

    t

  • 24

    t

  • 25

    Stopping distance formula

    t

  • 26

    -20m/s²

  • 27

    Write all equation of motion all six

    t

  • 28

    Acceleration does not represent motion

    t

  • 29

    1

  • 30

    0m

  • 31

    24m

  • 32

    0.5m

  • 33

    400m

  • 34

    7:9

  • 35

    25√2km/h

  • 36

    y=4x

  • 37

    120m

  • 38

    112m

  • 39

    16

  • 40

    3

  • 41

    go on increasing with time

  • 42

    1

  • 43

    1m

  • 44

    2v/a

  • 45

    1m/s

  • 46

    If velocity and acceleration are in same direction then U turn is possible

    False

  • 47

    velocity and acceleration are in opposite direction then U turn is possible only when v=0

    true

  • 48

    1m

  • 49

    The initial velocity of a particle is 20m/s and retardation 2m/s² then find distance in 10 sec

    100m

  • 50

    The initial velocity of a particle is 20 m per second and retardation 2m/s² then find distance and displacement in 10th sec

    1m and 1m

  • 51

    29m

  • 52

    The initial velocity of a particle is 21m/s and retardation is 2 m per second square then distance in 11th second

    0.5m

  • 53

    The initial velocity of a particle is 21m/s and retardation is 2 m per second square then displacement in 11th second

    0

  • 54

    A body is moving with uniform acceleration describe 40 m in the first 5 second and 65 m in next 5 second its initial velocity will be

    5.5m/s

  • 55

    Object starts is Motion from rest and constant acceleration takes time T for S displacement then time taken for first half and second half displacement is

    t

  • 56

    Object starts is Motion from rest and constant acceleration and travels with acceleration a for some time t1 then it retards with B and comes to at rest in time t2 then find total distance travelled and Vmax Write all for formulas of rest 2 rest motion

    t

  • 57

    A body starts from rest and acceleration 2 m per second square till it attains the maximum velocity then returnas to rest with 3 m per second square is total time is 10 seconds then maximum speed

    12 m per second

  • 58

    4

  • 59

    1

  • 60

    29m

  • 61

    260m

  • 62

    Find displacement in the given question not distance

    240m

  • 63

    Motion under gravity Draw graph for v=gt S=1/2gt² Acceleration versus time

    t

  • 64

    80m

  • 65

    A body falls from rest in the gravity of earth and distance travelled in 5th second is

    45m

  • 66

    A body falls from rest in the gravity of earth and distance travelled in 45th second is

    445m

  • 67

    t

  • 68

    20 m per second

  • 69

    125m

  • 70

    125m

  • 71

    both

  • 72

    Answer in fraction

    5/3m

  • 73

    3.75m

  • 74

    Ball is projected upward with velocity 50 m/s then find time of flight

    10 second

  • 75

    Ball is projected upward with velocity 50 m/s then find maximum height

    125 m

  • 76

    Ball is projected upward with velocity 50 m/s then find displacement in 6 second

    120m

  • 77

    Ball is projected upward with velocity 50 m/s then find height at 7 second

    105 m

  • 78

    Ball is projected upward with velocity 50 m/s then find average velocity in 8 second

    10 m per second

  • 79

    Ball is projected upward with velocity 50 m/s then find average speed in 8 second

    170/8 meter per second

  • 80

    20 m/s and 200/8 m/s

  • 81

    3

  • 82

    2

  • 83

    20 m

  • 84

    845 m

  • 85

    80 m

  • 86

    96 m

  • 87

    t

  • 88

    8H/9

  • 89

    5 second

  • 90

    7 second

  • 91

    105 m

  • 92

    t

  • 93

    2

  • 94

    125 m

  • 95

    6 second

  • 96

    t

  • 97

    10 second

  • 98

    20 m

  • 99

    6 second

  • 100

    t