physics
問題一覧
1
false
2
a force sustained for a long time produces more change in momentum than does the same force applied briefly.
3
this allows your hand to move backward while catching the ball, greater time of catch means less force on your hand.
4
with your hand against the wall, there is less time for momentum change, which means more force on your hand.
5
greater time for momentum to change means less force
6
case (3) because it is case (1) and (2) combined
7
case 3 because impulse is greater when the change in momentum is greater.
8
it is the same speed as momentum is simply transferred from one car to the other.
9
speed after coupling is half as much as initially because the mass that moves is doubled.
10
it is the same for the product of each is the same (50kg)(2m)=(25kg)(4m)
11
it has nine times as much KE (as 32=9)
12
Its gain in KE will equal its decrease in PE, 10 kJ.
13
From Ft = ∆mv, ∆mv = Ft = (12 N)(2.0 s) = 24 N × s = 24 kg × m/s.
14
W = Fd = (20 N)(3.5 m) = 70 N × m = 70 J
15
PE = mgh = (1000 kg)(10 N/kg)(5 m) = 50,000 N × m = 50,000 J
16
ke=1/2mv^2= 1/2(84kg)(10m/s)^2=4200kg(m/s)^2=4200j
17
see problem solution sheet.
18
From the conservation of momentum, MomentumDaisy = momentum(Jeannie Beanie + Daisy) (20 kg)(6 m/s) = (40 kg + 20 kg)v 120 kg × m/s = (60 kg)v v = (120 kg × m/s)/(60 kg) = 2 m/s
19
see problem solution sheet
20
a) PE = mgh = (10 kg)(10 N/kg)(0.3 m) = 30 N × m = 30 J (b) Height raised is (1.0 m – 0.3 m) = 0.7 m. W = Fd = mgh = (10 kg)(10 N/kg)(0.7 m) = 70 N·m = 70 J. (c) The KE of the barbell as it hits the floor (where h = 0) equals the PE lost by the barbell in falling, 30 J + 70 J = 100 J. So all that 100 J of PE becomes KE
21
∆KE = work done = Fd = (100 N – 70 N)(10 m) = (30 N)(10 m) = 300 N×m = 300 J
22
see problem 64 ch.3 solutions
23
Airbags lengthen the time of impact thereby reducing the force of impact.
24
Crumpling allows more time for reducing the momentum of the car, resulting in a smaller force of impact on the occupants
25
Although the impulses may be the same for the two cases, the times of impact are not. When the egg strikes the wall, impact time is short and impact force is correspondingly large. The egg breaks. But when the egg strikes the sagging sheet, impact time is long and the impact force is correspondingly small.
26
The total (net) momentum is zero. That’s true whatever their masses, for each will have the same amount of momentum but in the opposite direction from the other.
27
If no momentum is imparted to the ball, no oppositely directed momentum will be imparted to the thrower. Going through the motions of throwing has no net effect. If at the beginning of the throw you begin recoiling backward, at the end of the throw when you stop the motion of your arm and hold onto the ball, you stop moving too. Your position may change a little, but you end up at rest. No momentum given to the ball means no recoil momentum gained by you.
28
Your friend does twice as much work (4d ´ half the force > d ´ the same force)
29
Work done by each is the same, for they reach the same height. The one who climbs in 30 s uses more power because work is done in a shorter time
30
When a cannon with a long barrel is fired, more work is done as the cannonball is pushed through a longer distance. A greater KE is the result of the greater work, so of course, the cannonball emerges with a greater velocity. (Note that the force acting on the cannonball is not constant, but decreases with increasing distance inside the barrel.)
31
The KE of a pendulum bob is maximum where it moves fastest, at the lowest point; PE is maximum at the highest points. When the pendulum bob swings by the point that marks half its maximum height, it has half its maximum KE, and its PE is halfway between its minimum and maximum values. If we define PE = 0 at the bottom of the swing, the place where KE is half its maximum value is also the place where PE is half its maximum value, and KE = PE at this point. (Via energy conservation: Total energy = KE + PE.)
32
The 100 J of potential energy that doesn’t go into increasing her kinetic energy goes into thermal energy—heating her bottom and the slide
33
When the mass is doubled with no change in speed, both momentum and KE are doubled.
34
When the velocity is doubled, the momentum is doubled and the KE is increased by a factor of 4. Momentum is proportional to speed, and KE to speed squared
35
The force of gravity is one-ninth as much.
36
You’re closer to Earth’s center at sea level, so you weigh more there than on any mountain peak.
37
Springs would be more compressed when accelerating upward; less compressed when accelerating downward.
38
There are no changes in compression when moving at constant velocity
39
With no air resistance the horizontal component of velocity remains constant.
40
Neglecting air resistance, the vertical component of velocity decreases as the stone rises, and increases as the stone falls, the same as with any freely falling object
41
see ch4 solutions #36
42
see ch4 #37
43
see ch4 #42
44
see ch4 #42
45
see ch4 #49
46
Because of the independence of horizontal and vertical components of velocity, the falling time depends only on height y. Since there is no initial velocity in the vertical direction, the vertical distance is simply y = 1/2 gt2 (as learned in Chapter 2). (b) y = 1/2 gt2 = 1/2(9.8 m/s2)(2 s)2 = 19.6 m (or 20 m for g = 10 m/s2) (c) The horizontal and vertical components of velocity are independent of each other, which means falling distance is not affected by the horizontal component of velocity. Hence the bridge height is simply the height required for a freely falling rock to fall a vertical distance y. That’s y = 1/2 gt2 (as we learned in Chapter 2
47
The path would be a straight line in accord with the law of inertia.
48
Nearer the Moon.
49
Your weight would decrease if the Earth expanded with no change in its mass and would increase if the Earth contracted with no change in its mass. Your mass and the Earth’s mass don’t change, but the distance between you and the Earth’s center does change. Force is proportional to the inverse square of this distance.
50
Gravitational force is measured with respect to distance from Earth’s center. Since the workplaces are practically the same distance from Earth’s center any difference due to gravity is negligible
51
Due to the bulge a person in Singapore is farther from the Earth’s center and therefore weighs less there. The spin of the Earth contributes to even less weight in equatorial regions, although in practice these effects are minuscule
52
The pencil has the same motion that you have. The force of gravity on the pencil causes it to accelerate downward alongside of you. Although the pencil hovers relative to you, the pencil and you are falling relative to Earth
53
Since the ball moves horizontally off the edge of the table, speed does not affect the time to reach the can. Time of fall is independent of horizontal velocity
54
There are no forces horizontally (neglecting air resistance), so there is no horizontal acceleration, and hence the horizontal component of velocity doesn’t change. Gravitation acts vertically, which is why the vertical component of velocity changes
55
The crate will not hit the Corvette, but will crash a distance beyond it determined by the height and speed of the plane.
56
Hang time depends only on the vertical component of your lift-off velocity. If you can increase this vertical component from a running position rather than from a dead stop, perhaps by bounding harder against the ground, then hang time is also increased. In any case, hang time depends only on the vertical component of your lift-off velocity
57
The hang time will be the same, in accord with the answer to the preceding exercise. Hang time is related to the vertical height attained in a jump, not on horizontal distance moved across a level floor.
58
For very slow-moving bullets, the dropping distance is comparable to the horizontal range, and the resulting parabola is easily noticed (the curved path of a bullet tossed sideways by hand, for example). For high speed bullets, the same drop occurs in the same time, but the horizontal distance traveled is so large that the trajectory is “stretched out” and hardly seems to curve at all. But it does curve. All bullets will drop equal distances in equal times, whatever their speed. (It is interesting to note that air resistance plays only a small role, since the air resistance acting downward is practically the same for a slow-moving or fast- moving bullet.)
59
The monkey is hit as the dart and monkey meet in midair. For a fast-moving dart, their meeting place is closer to the monkey’s starting point than for a slower-moving dart. The dart and monkey fall equal vertical distances—the monkey below the tree, and the dart below the line of sight—because they both fall with equal accelerations for equal times
60
Inertia is a property of matter.
61
Both the bird and Earth have the same speed horizontally before, during, and after the bird drops.
62
Acceleration is the same as before.
63
The net force is 10 N.
64
A heavy object has proportionally more mass. The greater weight is offset by the greater mass, so the ratio of force/mass remains the same.
65
2. Net force is 10 N – 4 N = 6 N. When air resistance reaches 10 N, the net force is 10 N – 10 N = 0.
66
Acceleration is zero
67
A heavier parachutist must fall faster for air resistance to balance weight.
68
Although the boxer-bag interaction can be great, the tissue-boxer interaction can only be small due to the small mass of the tissue
69
The reaction force is ‘the ball against the bat.’
70
A helicopter pushes air down, and as a reaction, air pushes the helicopter up
71
ch2#35
72
ch2 #36
73
Fnet = ma = (12 kg)(7.0 m/s2) = 84 kg·m/s2 = 84 N
74
ch2 #41
75
ch2#43
76
ch2#44
77
ch2#47
78
ch2 #48
79
ch2 #51
80
Note that the weight of the 80-kg firefighter is mg = 80 kg ´ 10 m/s2 = 800 N. So Fnet = (800 N – f) = ma = (80 kg)(4 m/s2) = 320 N. So f = 800 N – 320 N = 480 N. Note that the weight of the 80-kg firefighter is mg = 80 kg ´ 10 m/s2 = 800 N. So Fnet = (800 N – f) = ma = (80 kg)(4 m/s2) = 320 N. So f = 800 N – 320 N = 480 N.
81
With no force of gravity on the Moon it would travel in a straight-line path.
82
You exert a force to overcome the force of friction. This makes the net force zero, which is why the wagon moves without acceleration. If you pull harder, then net force will be greater than zero and acceleration will occur.
83
Mainly the first law, for the bag in motion tends to continue in motion, which results in a squashed hand.
84
The net force is mg, 10 N (or more precisely, 9.8 N). With air resistance the net force is 10 N – 2 N = 8 N (or more precisely 9.8 N – 2 N = 7.8 N).
85
a) Action; hammer strikes nail. Reaction; nail strikes hammer. (b) Action; Earth pulls down on a book. Reaction; book pulls up on Earth. (c) Action; helicopter blade pushes air downward. Reaction; air pushes helicopter blade upward. (In these examples, action and reaction may be reversed—which is labeled which is unimportant.)
86
The terminal speed attained by the falling cat is the same whether it falls from 50 stories or 20 stories. Once terminal speed is reached, falling extra distance does not affect the speed. (The low terminal velocities of small creatures enable them to fall without harm from heights that would kill larger creatures.)
87
a) A skydiver encountering NO air resistance is in free fall. But a diver falling in air at terminal velocity encounters air resistance and is not in free fall. (b) The only force acting on a satellite is that due to gravity, so a satellite is in free fall (more about this in Chapter 4).
88
say to your friend that the skydiver is still speeding up but at an ever-slower rate of increase, which means acceleration is decreasing. Eventually the acceleration will become zero, in which case the diver has reached terminal velocity
89
Yes, an upward support force acts on you while standing on a floor, which is equal and opposite to the force of gravity on you—your weight. You are not moved upward by this force because it is only one of two vertical forces acting on you, making the net force zero.
90
When you pull up on the handlebars, the handlebars in turn pull down on you. This downward force is transmitted to the pedals.
91
As in the preceding exercise, the force on each cart will be the same. But since the masses are different, the accelerations will differ. The twice-as-massive cart will undergo only half the acceleration of the less massive cart and will gain only half the speed
92
In accord with Newton’s 3rd law, the force on each will be of the same magnitude. But the effect of the force (acceleration) will be different for each because of the different mass. The more massive truck undergoes less change in motion than the motorcycle.
93
Agree. Acceleration (slowing the car) is opposite to velocity (the direction the car is moving).
94
With air resistance water drops fall at a tolerable terminal speed. Without air resistance water drops would be in free fall, and depending on the height of the clouds, speeds of impact would be hazardous
95
When the coin goes up the velocity decreases by 10 m/s each second. Its acceleration, however, remains constant (which is why the constant change of 10 m/s each second). At the top its acceleration is 10 m/s2 .
96
Neither a stick of dynamite, a fist, a hammer, nor anything else “contains” force. We will see later that a stick of dynamite contains energy, which like a fist or hammer is capable of producing forces when an interaction of some kind occurs
97
When the bus slows, you tend to keep moving at the previous speed and lurch forward. When the bus picks up speed, you tend to keep moving at the previous (lower) speed and you lurch backward. The law of inertia applies in both cases
98
After leaving your hand its speed would be greater than if dropped, but its acceleration would be the same 10 m/s2 downward because only Earth’s pull acts on it.
99
With no air resistance the ball returns as fast as it was thrown. When air resistance affects motion, the ball returns to its starting level with less speed than its initial speed,With no air resistance the ball returns as fast as it was thrown. When air resistance affects motion, the ball returns to its starting level with less speed than its initial speed,
100
see week3 homework
問題一覧
1
false
2
a force sustained for a long time produces more change in momentum than does the same force applied briefly.
3
this allows your hand to move backward while catching the ball, greater time of catch means less force on your hand.
4
with your hand against the wall, there is less time for momentum change, which means more force on your hand.
5
greater time for momentum to change means less force
6
case (3) because it is case (1) and (2) combined
7
case 3 because impulse is greater when the change in momentum is greater.
8
it is the same speed as momentum is simply transferred from one car to the other.
9
speed after coupling is half as much as initially because the mass that moves is doubled.
10
it is the same for the product of each is the same (50kg)(2m)=(25kg)(4m)
11
it has nine times as much KE (as 32=9)
12
Its gain in KE will equal its decrease in PE, 10 kJ.
13
From Ft = ∆mv, ∆mv = Ft = (12 N)(2.0 s) = 24 N × s = 24 kg × m/s.
14
W = Fd = (20 N)(3.5 m) = 70 N × m = 70 J
15
PE = mgh = (1000 kg)(10 N/kg)(5 m) = 50,000 N × m = 50,000 J
16
ke=1/2mv^2= 1/2(84kg)(10m/s)^2=4200kg(m/s)^2=4200j
17
see problem solution sheet.
18
From the conservation of momentum, MomentumDaisy = momentum(Jeannie Beanie + Daisy) (20 kg)(6 m/s) = (40 kg + 20 kg)v 120 kg × m/s = (60 kg)v v = (120 kg × m/s)/(60 kg) = 2 m/s
19
see problem solution sheet
20
a) PE = mgh = (10 kg)(10 N/kg)(0.3 m) = 30 N × m = 30 J (b) Height raised is (1.0 m – 0.3 m) = 0.7 m. W = Fd = mgh = (10 kg)(10 N/kg)(0.7 m) = 70 N·m = 70 J. (c) The KE of the barbell as it hits the floor (where h = 0) equals the PE lost by the barbell in falling, 30 J + 70 J = 100 J. So all that 100 J of PE becomes KE
21
∆KE = work done = Fd = (100 N – 70 N)(10 m) = (30 N)(10 m) = 300 N×m = 300 J
22
see problem 64 ch.3 solutions
23
Airbags lengthen the time of impact thereby reducing the force of impact.
24
Crumpling allows more time for reducing the momentum of the car, resulting in a smaller force of impact on the occupants
25
Although the impulses may be the same for the two cases, the times of impact are not. When the egg strikes the wall, impact time is short and impact force is correspondingly large. The egg breaks. But when the egg strikes the sagging sheet, impact time is long and the impact force is correspondingly small.
26
The total (net) momentum is zero. That’s true whatever their masses, for each will have the same amount of momentum but in the opposite direction from the other.
27
If no momentum is imparted to the ball, no oppositely directed momentum will be imparted to the thrower. Going through the motions of throwing has no net effect. If at the beginning of the throw you begin recoiling backward, at the end of the throw when you stop the motion of your arm and hold onto the ball, you stop moving too. Your position may change a little, but you end up at rest. No momentum given to the ball means no recoil momentum gained by you.
28
Your friend does twice as much work (4d ´ half the force > d ´ the same force)
29
Work done by each is the same, for they reach the same height. The one who climbs in 30 s uses more power because work is done in a shorter time
30
When a cannon with a long barrel is fired, more work is done as the cannonball is pushed through a longer distance. A greater KE is the result of the greater work, so of course, the cannonball emerges with a greater velocity. (Note that the force acting on the cannonball is not constant, but decreases with increasing distance inside the barrel.)
31
The KE of a pendulum bob is maximum where it moves fastest, at the lowest point; PE is maximum at the highest points. When the pendulum bob swings by the point that marks half its maximum height, it has half its maximum KE, and its PE is halfway between its minimum and maximum values. If we define PE = 0 at the bottom of the swing, the place where KE is half its maximum value is also the place where PE is half its maximum value, and KE = PE at this point. (Via energy conservation: Total energy = KE + PE.)
32
The 100 J of potential energy that doesn’t go into increasing her kinetic energy goes into thermal energy—heating her bottom and the slide
33
When the mass is doubled with no change in speed, both momentum and KE are doubled.
34
When the velocity is doubled, the momentum is doubled and the KE is increased by a factor of 4. Momentum is proportional to speed, and KE to speed squared
35
The force of gravity is one-ninth as much.
36
You’re closer to Earth’s center at sea level, so you weigh more there than on any mountain peak.
37
Springs would be more compressed when accelerating upward; less compressed when accelerating downward.
38
There are no changes in compression when moving at constant velocity
39
With no air resistance the horizontal component of velocity remains constant.
40
Neglecting air resistance, the vertical component of velocity decreases as the stone rises, and increases as the stone falls, the same as with any freely falling object
41
see ch4 solutions #36
42
see ch4 #37
43
see ch4 #42
44
see ch4 #42
45
see ch4 #49
46
Because of the independence of horizontal and vertical components of velocity, the falling time depends only on height y. Since there is no initial velocity in the vertical direction, the vertical distance is simply y = 1/2 gt2 (as learned in Chapter 2). (b) y = 1/2 gt2 = 1/2(9.8 m/s2)(2 s)2 = 19.6 m (or 20 m for g = 10 m/s2) (c) The horizontal and vertical components of velocity are independent of each other, which means falling distance is not affected by the horizontal component of velocity. Hence the bridge height is simply the height required for a freely falling rock to fall a vertical distance y. That’s y = 1/2 gt2 (as we learned in Chapter 2
47
The path would be a straight line in accord with the law of inertia.
48
Nearer the Moon.
49
Your weight would decrease if the Earth expanded with no change in its mass and would increase if the Earth contracted with no change in its mass. Your mass and the Earth’s mass don’t change, but the distance between you and the Earth’s center does change. Force is proportional to the inverse square of this distance.
50
Gravitational force is measured with respect to distance from Earth’s center. Since the workplaces are practically the same distance from Earth’s center any difference due to gravity is negligible
51
Due to the bulge a person in Singapore is farther from the Earth’s center and therefore weighs less there. The spin of the Earth contributes to even less weight in equatorial regions, although in practice these effects are minuscule
52
The pencil has the same motion that you have. The force of gravity on the pencil causes it to accelerate downward alongside of you. Although the pencil hovers relative to you, the pencil and you are falling relative to Earth
53
Since the ball moves horizontally off the edge of the table, speed does not affect the time to reach the can. Time of fall is independent of horizontal velocity
54
There are no forces horizontally (neglecting air resistance), so there is no horizontal acceleration, and hence the horizontal component of velocity doesn’t change. Gravitation acts vertically, which is why the vertical component of velocity changes
55
The crate will not hit the Corvette, but will crash a distance beyond it determined by the height and speed of the plane.
56
Hang time depends only on the vertical component of your lift-off velocity. If you can increase this vertical component from a running position rather than from a dead stop, perhaps by bounding harder against the ground, then hang time is also increased. In any case, hang time depends only on the vertical component of your lift-off velocity
57
The hang time will be the same, in accord with the answer to the preceding exercise. Hang time is related to the vertical height attained in a jump, not on horizontal distance moved across a level floor.
58
For very slow-moving bullets, the dropping distance is comparable to the horizontal range, and the resulting parabola is easily noticed (the curved path of a bullet tossed sideways by hand, for example). For high speed bullets, the same drop occurs in the same time, but the horizontal distance traveled is so large that the trajectory is “stretched out” and hardly seems to curve at all. But it does curve. All bullets will drop equal distances in equal times, whatever their speed. (It is interesting to note that air resistance plays only a small role, since the air resistance acting downward is practically the same for a slow-moving or fast- moving bullet.)
59
The monkey is hit as the dart and monkey meet in midair. For a fast-moving dart, their meeting place is closer to the monkey’s starting point than for a slower-moving dart. The dart and monkey fall equal vertical distances—the monkey below the tree, and the dart below the line of sight—because they both fall with equal accelerations for equal times
60
Inertia is a property of matter.
61
Both the bird and Earth have the same speed horizontally before, during, and after the bird drops.
62
Acceleration is the same as before.
63
The net force is 10 N.
64
A heavy object has proportionally more mass. The greater weight is offset by the greater mass, so the ratio of force/mass remains the same.
65
2. Net force is 10 N – 4 N = 6 N. When air resistance reaches 10 N, the net force is 10 N – 10 N = 0.
66
Acceleration is zero
67
A heavier parachutist must fall faster for air resistance to balance weight.
68
Although the boxer-bag interaction can be great, the tissue-boxer interaction can only be small due to the small mass of the tissue
69
The reaction force is ‘the ball against the bat.’
70
A helicopter pushes air down, and as a reaction, air pushes the helicopter up
71
ch2#35
72
ch2 #36
73
Fnet = ma = (12 kg)(7.0 m/s2) = 84 kg·m/s2 = 84 N
74
ch2 #41
75
ch2#43
76
ch2#44
77
ch2#47
78
ch2 #48
79
ch2 #51
80
Note that the weight of the 80-kg firefighter is mg = 80 kg ´ 10 m/s2 = 800 N. So Fnet = (800 N – f) = ma = (80 kg)(4 m/s2) = 320 N. So f = 800 N – 320 N = 480 N. Note that the weight of the 80-kg firefighter is mg = 80 kg ´ 10 m/s2 = 800 N. So Fnet = (800 N – f) = ma = (80 kg)(4 m/s2) = 320 N. So f = 800 N – 320 N = 480 N.
81
With no force of gravity on the Moon it would travel in a straight-line path.
82
You exert a force to overcome the force of friction. This makes the net force zero, which is why the wagon moves without acceleration. If you pull harder, then net force will be greater than zero and acceleration will occur.
83
Mainly the first law, for the bag in motion tends to continue in motion, which results in a squashed hand.
84
The net force is mg, 10 N (or more precisely, 9.8 N). With air resistance the net force is 10 N – 2 N = 8 N (or more precisely 9.8 N – 2 N = 7.8 N).
85
a) Action; hammer strikes nail. Reaction; nail strikes hammer. (b) Action; Earth pulls down on a book. Reaction; book pulls up on Earth. (c) Action; helicopter blade pushes air downward. Reaction; air pushes helicopter blade upward. (In these examples, action and reaction may be reversed—which is labeled which is unimportant.)
86
The terminal speed attained by the falling cat is the same whether it falls from 50 stories or 20 stories. Once terminal speed is reached, falling extra distance does not affect the speed. (The low terminal velocities of small creatures enable them to fall without harm from heights that would kill larger creatures.)
87
a) A skydiver encountering NO air resistance is in free fall. But a diver falling in air at terminal velocity encounters air resistance and is not in free fall. (b) The only force acting on a satellite is that due to gravity, so a satellite is in free fall (more about this in Chapter 4).
88
say to your friend that the skydiver is still speeding up but at an ever-slower rate of increase, which means acceleration is decreasing. Eventually the acceleration will become zero, in which case the diver has reached terminal velocity
89
Yes, an upward support force acts on you while standing on a floor, which is equal and opposite to the force of gravity on you—your weight. You are not moved upward by this force because it is only one of two vertical forces acting on you, making the net force zero.
90
When you pull up on the handlebars, the handlebars in turn pull down on you. This downward force is transmitted to the pedals.
91
As in the preceding exercise, the force on each cart will be the same. But since the masses are different, the accelerations will differ. The twice-as-massive cart will undergo only half the acceleration of the less massive cart and will gain only half the speed
92
In accord with Newton’s 3rd law, the force on each will be of the same magnitude. But the effect of the force (acceleration) will be different for each because of the different mass. The more massive truck undergoes less change in motion than the motorcycle.
93
Agree. Acceleration (slowing the car) is opposite to velocity (the direction the car is moving).
94
With air resistance water drops fall at a tolerable terminal speed. Without air resistance water drops would be in free fall, and depending on the height of the clouds, speeds of impact would be hazardous
95
When the coin goes up the velocity decreases by 10 m/s each second. Its acceleration, however, remains constant (which is why the constant change of 10 m/s each second). At the top its acceleration is 10 m/s2 .
96
Neither a stick of dynamite, a fist, a hammer, nor anything else “contains” force. We will see later that a stick of dynamite contains energy, which like a fist or hammer is capable of producing forces when an interaction of some kind occurs
97
When the bus slows, you tend to keep moving at the previous speed and lurch forward. When the bus picks up speed, you tend to keep moving at the previous (lower) speed and you lurch backward. The law of inertia applies in both cases
98
After leaving your hand its speed would be greater than if dropped, but its acceleration would be the same 10 m/s2 downward because only Earth’s pull acts on it.
99
With no air resistance the ball returns as fast as it was thrown. When air resistance affects motion, the ball returns to its starting level with less speed than its initial speed,With no air resistance the ball returns as fast as it was thrown. When air resistance affects motion, the ball returns to its starting level with less speed than its initial speed,
100
see week3 homework