ESAS part 2
問題一覧
1
Subcooling of the refrigerant in the condenser.
2
Heat and humidify.
3
Dew-point temperature
4
90 km/h
5
5 h 3 min
6
32.3 m/s^2
7
2.4 s
8
70 m/s
9
4 m
10
2050 m
11
0.97 m
12
24.7 m
13
4.5 s
14
171 m
15
60 m
16
3.8g
17
23.9
18
central processing unit
19
Foreign Reciprocity
20
8
21
PHP 4,256,782
22
twice
23
motherboard
24
Fe
25
All of these
26
Shot peening
27
Php 670.98
28
0.45
29
inversely proportional to square root of molecular mass
30
The head developed is due to the push of the vanes and flow is almost entirely axial.
31
A series of uniforms amounts over a period of time.
32
Potassium
33
9.31%
34
evaluating over different time periods
35
repay the loan over an agreed-upon amount of time
36
сrеер
37
Liquidity
38
Trojan horse
39
RAMs
40
Thrashing
41
framing members
42
framing members
43
wiring design rule
44
Open system
45
Open system
46
Increases as the same rate as the area of the metal increases
47
1 m/s
48
kinetic energy
49
200 N
50
21
51
(quantity issued - standard quantity)(standard price)
52
1/2
53
57.23%
54
The areas closest to the axis of interest are the most significant.
55
all of these
56
isomers
57
Cold work decreases the yield point of the metal.
58
11%
59
Compression of air in a cylinder
60
Heat and humidify.
61
Beginner's All-Purpose Symbolic Instruction Code
62
l only
63
Blogging
64
Use of proper tools
65
non payment of debts
66
Grounded Conductor
67
A series of uniform amounts over a period of time.
68
50%
69
both I and Il
70
Ctrl+End
71
identified
72
Turn on the cable modem, then the router, and then the computer
73
0.3 MJ
74
Fiber To The Home
75
16g of oxygen molecules
76
metallic
77
1.37
78
(A/F,i,n)-i=(A/P,i,n)
79
Na
80
Tf = 9/5 Tc + 32
81
organizing
82
Francis Mapile
83
Steiner's theorem
84
compound amount factor
85
Р14.90
86
programming language
87
linear
88
2 5 0 0
89
virtual memory
90
Market
91
set goals
92
Pascal's principle
93
9136
94
5.4 J
95
$69,500
96
19.45%
97
20 %
98
It can be determined using the simplex logarithm.
99
0.512
100
The value of I cannot be changed in the DO loop.
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1
Subcooling of the refrigerant in the condenser.
2
Heat and humidify.
3
Dew-point temperature
4
90 km/h
5
5 h 3 min
6
32.3 m/s^2
7
2.4 s
8
70 m/s
9
4 m
10
2050 m
11
0.97 m
12
24.7 m
13
4.5 s
14
171 m
15
60 m
16
3.8g
17
23.9
18
central processing unit
19
Foreign Reciprocity
20
8
21
PHP 4,256,782
22
twice
23
motherboard
24
Fe
25
All of these
26
Shot peening
27
Php 670.98
28
0.45
29
inversely proportional to square root of molecular mass
30
The head developed is due to the push of the vanes and flow is almost entirely axial.
31
A series of uniforms amounts over a period of time.
32
Potassium
33
9.31%
34
evaluating over different time periods
35
repay the loan over an agreed-upon amount of time
36
сrеер
37
Liquidity
38
Trojan horse
39
RAMs
40
Thrashing
41
framing members
42
framing members
43
wiring design rule
44
Open system
45
Open system
46
Increases as the same rate as the area of the metal increases
47
1 m/s
48
kinetic energy
49
200 N
50
21
51
(quantity issued - standard quantity)(standard price)
52
1/2
53
57.23%
54
The areas closest to the axis of interest are the most significant.
55
all of these
56
isomers
57
Cold work decreases the yield point of the metal.
58
11%
59
Compression of air in a cylinder
60
Heat and humidify.
61
Beginner's All-Purpose Symbolic Instruction Code
62
l only
63
Blogging
64
Use of proper tools
65
non payment of debts
66
Grounded Conductor
67
A series of uniform amounts over a period of time.
68
50%
69
both I and Il
70
Ctrl+End
71
identified
72
Turn on the cable modem, then the router, and then the computer
73
0.3 MJ
74
Fiber To The Home
75
16g of oxygen molecules
76
metallic
77
1.37
78
(A/F,i,n)-i=(A/P,i,n)
79
Na
80
Tf = 9/5 Tc + 32
81
organizing
82
Francis Mapile
83
Steiner's theorem
84
compound amount factor
85
Р14.90
86
programming language
87
linear
88
2 5 0 0
89
virtual memory
90
Market
91
set goals
92
Pascal's principle
93
9136
94
5.4 J
95
$69,500
96
19.45%
97
20 %
98
It can be determined using the simplex logarithm.
99
0.512
100
The value of I cannot be changed in the DO loop.